Forging (old) - Revision history

CARAAMON at 08:10, 20 January 2015

2015-01-20T08:10:37Z

← Older revision		Revision as of 03:10, 20 January 2015
Line 175:		Line 175:
	* [[Weapon mixes]]		* [[Weapon mixes]]
	* [[Armor mixes]]		* [[Armor mixes]]
			{{cat\|Creation systems}}


	[[Category:Creation Systems]]

Maintenance script at 15:19, 1 July 2013

2013-07-01T15:19:22Z

← Older revision		Revision as of 10:19, 1 July 2013
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			{{Obsolete\|Replaced by new [[Forging]] system}}
	It is possible to create weapons and [[armor]] through the forging system. There are two parts to the process: smelting (mixing), which requires knowledge of the materials; and crafting (pounding), which requires physical stats and the appropriate weapon or armor skills.		It is possible to create weapons and [[armor]] through the forging system. There are two parts to the process: smelting (mixing), which requires knowledge of the materials; and crafting (pounding), which requires physical stats and the appropriate weapon or armor skills.

CARAAMON: moved Forging to Forging (old)

2013-03-14T11:39:07Z

moved Forging to Forging (old)

← Older revision	Revision as of 06:39, 14 March 2013
(No difference)

CARAAMON: retreiving old info for archiving

2013-03-14T11:38:50Z

retreiving old info for archiving

Show changes

CARAAMON: Redirected page to Forging craft

2013-01-13T01:24:32Z

Redirected page to Forging craft

← Older revision		Revision as of 20:24, 12 January 2013
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	#REDIRECT [[~~Crafting~~]]		#REDIRECT [[Forging craft]]

CARAAMON: Redirected to the new forging system

2011-09-24T23:28:11Z

Redirected to the new forging system

Show changes

DRTYPRIOR at 04:18, 23 March 2011

2011-03-23T04:18:20Z

← Older revision		Revision as of 23:18, 22 March 2011
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	WARNING: Much of the information below is a few years old. Some details may have changed.		WARNING: Much of the information below is a few years old. Some details may have changed.
			:*Updated [[Blacksmithing]] for 3.0

	==Weapon volumes==		==Weapon volumes==

Maintenance script: /* Compression */

2010-05-09T01:32:35Z

Compression

← Older revision		Revision as of 20:32, 8 May 2010
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	As an additional note from Gavinne, there are two forms of 'compression' so the term can be misleading if you do not know which form is being spoken of.		As an additional note from Gavinne, there are two forms of 'compression' so the term can be misleading if you do not know which form is being spoken of.

	One form of compression, which really isn't compression at all, is when you have a 200 stone ingot and pound it into a scimitar, yet the scimitar only weighs 22 stones. Folks began calling this 'compression' due to a lack of understanding and hopefully this will help clear some things up. The general formula for determining an items weight is (Total Mix Weight/Total Mix Volume)Volume Required For Item, or (W/V)R. Basically, if you have a 5 pound block of steel which has a volume of 3 cubic feet and make something out of it that only needs to use 1 cubic feet, your item will weigh (5/3)1 pounds, the excess metal is thrown away since it is not used. To further this example, lets say we have a mix like '3 tin slugs, melt and mix them together, add 2 dusts, melt and mix, add 2 more dusts, melt and mix, add an iron bar, melt and mix, then add a final dust, melt and stir.' or, in short, 3 tin slugs MIX 2 dusts MIX 2 dusts MIX 1 iron bar MIX 1 dust MIX. The final dust is to make it steel so that will not be counted as it does not add weight or volume (when carbonizing steel the volume and weight of the dust used to carbonize is not added) so we will not include that, this leaves us with 4 dusts, 3 tin slugs, and an iron bar. iron bar is 51 stones, tin slugs are 7 stones each, dusts are 2 stones each, thus our total weight is 80 stones. For volume, iron bar is 10 slugs, tin slugs are 1 slug each, dusts are 2 slugs each, so our total volume is 20 slugs. 80 stones divided by 20 slugs is 4 so our Average Weight per Unit of Volume is 4. If we were to make that mix into some gauntlets, our gauntlets would weigh 410 since gauntlets have a volume of 10, if we were to make that mix into a scimitar the scimitar, which has a volume of 6, our scimitar would weigh 4 stones * 6. The excess material which we do not use is thrown away, hence this is not really compression at all, it is simply using what you need from the ingot, plate, or wire and throwing the rest away. To further explain, if we take an iron bar, which has a weight of 51 and a volume of 10, and make it into a broadsword which requires a volume of 7, our broadsword would weigh (51/10)*7 stones because we would only use 7 out of 10 of the volume, the other 3 is thrown away. At this point I would like to note that Dragon Realms always rounds DOWN, so if your item is 34.9999999 stones, upon completion it will be 34 stones, just like if your item would be 58.12345 stones, upon completion it will weigh 58 stones.		One form of compression, which really isn't compression at all, is when you have a 200 stone ingot and pound it into a scimitar, yet the scimitar only weighs 22 stones. Folks began calling this 'compression' due to a lack of understanding and hopefully this will help clear some things up. The general formula for determining an items weight is (Total Mix Weight/Total Mix Volume)Volume Required For Item, or (W/V)R. Basically, if you have a 5 pound block of steel which has a volume of 3 cubic feet and make something out of it that only needs to use 1 cubic feet, your item will weigh (5/3)1 pounds, the excess metal is thrown away since it is not used. To further this example, lets say we have a mix like '3 tin slugs, melt and mix them together, add 2 dusts, melt and mix, add 2 more dusts, melt and mix, add an iron bar, melt and mix, then add a final dust, melt and stir.' or, in short, 3 tin slugs MIX 2 dusts MIX 2 dusts MIX 1 iron bar MIX 1 dust MIX. The final dust is to make it steel so that will not be counted as it does not add weight or volume (when carbonizing steel the volume and weight of the dust used to carbonize is not added) so we will not include that, this leaves us with 4 dusts, 3 tin slugs, and an iron bar. iron bar is 51 stones, tin slugs are 7 stones each, dusts are 2 stones each, thus our total weight is 80 stones. For volume, iron bar is 10 slugs, tin slugs are 1 slug each, dusts are 2 slugs each, so our total volume is 20 slugs. 80 stones divided by 20 slugs is 4 so our Average Weight per Unit of Volume is 4. If we were to make that mix into some gauntlets, our gauntlets would weigh 410 since gauntlets have a volume of 10, if we were to make that mix into a scimitar the scimitar, which has a volume of 6, our scimitar would weigh 4 stones * 6. The excess material which we do not use is thrown away, hence this is not really compression at all, it is simply using what you need from the ingot, plate, or wire and throwing the rest away. To further explain, if we take an iron bar, which has a weight of 51 and a volume of 10, and make it into a broadsword which requires a volume of 7, our broadsword would weigh (51/10)7 stones because we would only use 7 out of 10 of the volume, the other 3 is thrown away. At this point I would like to note that Dragon Realms always rounds DOWN, so if your item is 34.9999999 stones, upon completion it will be 34 stones, just like if your item would be 58.12345 stones, upon completion it will weigh 58 stones. Once more to make sure everyone understands, to find the weight of an item you take the Total Weight of the mixture and divide it by the Total Volume of the mixture, this gives us the Average Weight. If you have an iron bar which is 51 stones and 10 slugs, 51/10 = 5.1. So that means each 1 unit of volume in that bar weighs 5.1 stones. We then multiply the Average Weight by the volume of the item we want to make, for example a mace which takes a volume of 9 to make. 51 stones/10 slugs (iron bar) = 5.1, 5.19(volume of mace) = 45.9 stone mace, dragon realms always rounds down so it would be a 45 stone mace.

	Another form of compression is an unintended but useful error in the mechanics of mixing in which the weight of something is added but not the volume. This has never been fixed, and will not be fixed until forging 2.0 is out due to the fact that without it we would have no way of making items heavier. To explain, compression of this type is based on even and odd numbers of volume. If you mix two different types of metal together, and one has an odd volume number while the other has an even volume number, 1 unit of volume will compress and its weight will be added but not its volume. This is a bit confusing so please bear with me as I attempt to explain. If you have 1 iron bar which has a volume of 10 and it with 1 zinc slug which has a volume of 1, the zinc slugs weight will be added but not its volume, thus 1 iron bar (volume 10, weight 51) plus 1 zinc slug (volume 1, weight 5) makes a mass with a volume of 10 and a weight of 56. By further example, if you mix two zinc slugs together, again each having a weight of 5 and a volume of 1, this will give us 10 stones total at 2 slugs volume. If then we add 3 lead slugs (each having volume of 1 and weight of 8) then by normal thinking it SHOULD give us 5+5+8+8+8=34 weight at 1+1+1+1+1=5 volume, but it does not due to compression. 2 (even) zinc slugs plus 3 (odd) lead slugs will only give us a volume of 4 because 1 unit of volume will compress, the weight will still be added so you will still have 34 stones of material, but due to compression (even+odd, or odd+even) 1 unit of volume will compress so we will only have a volume of 4. Again, to explain, 2+1=2, 3+2=4, 5+4=8, and so fourth due to compression. Theoretically you can make items infinitely heavier this way, since 2+1=2, you can continually add another single unit of volume to it and the weight will be added but, once again, not the volume, so 2+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1=2. A common example of this is 23 stone short swords and 39 stone katars. To make a 23 stone short sword or 39 stone katar, you start with an iron bar, which is 51 stones at 10 slugs of volume, and compress single slugs into it one at a time until you reach 78 stones, you can use any non-iron slug metal slug you want for this such a 2 nickel slugs and 3 zinc slugs, or 2 copper slug and 3 zinc slugs, or 2 lead slugs 1 zinc slug and 1 copper slug, or any other combonation as long as they are a metal other than iron they will compress when mixed one at a time because 10+1+1+1+1+1+1+1+1+1+1+1+1+1+1=10. each time you mix a single slug into the iron bar its weight will be added but NOT its volume.		Another form of compression is an unintended but useful error in the mechanics of mixing in which the weight of something is added but not the volume. This has never been fixed, and will not be fixed until forging 2.0 is out due to the fact that without it we would have no way of making items heavier. To explain, compression of this type is based on even and odd numbers of volume. If you mix two different types of metal together, and one has an odd volume number while the other has an even volume number, 1 unit of volume will compress and its weight will be added but not its volume. This is a bit confusing so please bear with me as I attempt to explain. If you have 1 iron bar which has a volume of 10 and it with 1 zinc slug which has a volume of 1, the zinc slugs weight will be added but not its volume, thus 1 iron bar (volume 10, weight 51) plus 1 zinc slug (volume 1, weight 5) makes a mass with a volume of 10 and a weight of 56. By further example, if you mix two zinc slugs together, again each having a weight of 5 and a volume of 1, this will give us 10 stones total at 2 slugs volume. If then we add 3 lead slugs (each having volume of 1 and weight of 8) then by normal thinking it SHOULD give us 5+5+8+8+8=34 weight at 1+1+1+1+1=5 volume, but it does not due to compression. 2 (even) zinc slugs plus 3 (odd) lead slugs will only give us a volume of 4 because 1 unit of volume will compress, the weight will still be added so you will still have 34 stones of material, but due to compression (even+odd, or odd+even) 1 unit of volume will compress so we will only have a volume of 4. Again, to explain, 2+1=2, 3+2=4, 5+4=8, and so fourth due to compression. Theoretically you can make items infinitely heavier this way, since 2+1=2, you can continually add another single unit of volume to it and the weight will be added but, once again, not the volume, so 2+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1=2. A common example of this is 23 stone short swords and 39 stone katars. To make a 23 stone short sword or 39 stone katar, you start with an iron bar, which is 51 stones at 10 slugs of volume, and compress single slugs into it one at a time until you reach 78 stones, you can use any non-iron slug metal slug you want for this such a 2 nickel slugs and 3 zinc slugs, or 2 copper slug and 3 zinc slugs, or 2 lead slugs 1 zinc slug and 1 copper slug, or any other combonation as long as they are a metal other than iron they will compress when mixed one at a time because 10+1+1+1+1+1+1+1+1+1+1+1+1+1+1=10. each time you mix a single slug into the iron bar its weight will be added but NOT its volume.

Maintenance script: /* Compression */

2010-05-09T01:27:42Z

Compression

← Older revision		Revision as of 20:27, 8 May 2010
Line 162:		Line 162:
	As an additional note from Gavinne, there are two forms of 'compression' so the term can be misleading if you do not know which form is being spoken of.		As an additional note from Gavinne, there are two forms of 'compression' so the term can be misleading if you do not know which form is being spoken of.

	One form of compression, which really isn't compression at all, is when you have a 200 stone ingot and pound it into a scimitar, yet the scimitar only weighs 22 stones. Folks began calling this 'compression' due to a lack of understanding and hopefully this will help clear some things up. The general formula for determining an items weight is (Total Mix Weight/Total Mix Volume)Volume Required For Item, or (W/V)R. Basically, if you have a 5 pound block of steel which has a volume of 3 cubic feet and make something out of it that only needs to use 1 cubic feet, your item will weigh (5/3)1 pounds, the excess metal is thrown away since it is not used. To further this example, lets say we have a mix like '3 tin slugs, melt and mix them together, add 2 dusts, melt and mix, add 2 more dusts, melt and mix, add an iron bar, melt and mix, then add a final dust, melt and stir.' or, in short, 3 tin slugs MIX 2 dusts MIX 2 dusts MIX 1 iron bar MIX 1 dust MIX. The final dust is to make it steel so that will not be counted as it does not add weight or volume (when carbonizing steel the volume and weight of the dust used to carbonize is not added) so we will not include that, this leaves us with 4 dusts, 3 tin slugs, and an iron bar. iron bar is 51 stones, tin slugs are 7 stones each, dusts are 2 stones each, thus our total weight is 80 stones. For volume, iron bar is 10 slugs, tin slugs are 1 slug each, dusts are 2 slugs each, so our total volume is 20 slugs. 80 stones divided by 20 slugs is 4 so our Average Weight per Unit of Volume is 4. If we were to make that mix into some gauntlets, our gauntlets would weigh 410 since gauntlets have a volume of 10, if we were to make that mix into a scimitar the scimitar, which has a volume of 6, our scimitar would weigh 4 stones * 6. The excess material which we do not use is thrown away, hence this is not really compression at all, it is simply using what you need from the ingot, plate, or wire and throwing the rest away. To further explain, if we take an iron bar, which has a weight of 51 and a volume of 10, and make it into a broadsword which requires a volume of 7, our broadsword would weigh (51/10)*7 stones. At this point I would like to note that Dragon Realms always rounds DOWN, so if your item is 34.9999999 stones, upon completion it will be 34 stones, just like if your item would be 58.12345 stones, upon completion it will weigh 58 stones.		One form of compression, which really isn't compression at all, is when you have a 200 stone ingot and pound it into a scimitar, yet the scimitar only weighs 22 stones. Folks began calling this 'compression' due to a lack of understanding and hopefully this will help clear some things up. The general formula for determining an items weight is (Total Mix Weight/Total Mix Volume)Volume Required For Item, or (W/V)R. Basically, if you have a 5 pound block of steel which has a volume of 3 cubic feet and make something out of it that only needs to use 1 cubic feet, your item will weigh (5/3)1 pounds, the excess metal is thrown away since it is not used. To further this example, lets say we have a mix like '3 tin slugs, melt and mix them together, add 2 dusts, melt and mix, add 2 more dusts, melt and mix, add an iron bar, melt and mix, then add a final dust, melt and stir.' or, in short, 3 tin slugs MIX 2 dusts MIX 2 dusts MIX 1 iron bar MIX 1 dust MIX. The final dust is to make it steel so that will not be counted as it does not add weight or volume (when carbonizing steel the volume and weight of the dust used to carbonize is not added) so we will not include that, this leaves us with 4 dusts, 3 tin slugs, and an iron bar. iron bar is 51 stones, tin slugs are 7 stones each, dusts are 2 stones each, thus our total weight is 80 stones. For volume, iron bar is 10 slugs, tin slugs are 1 slug each, dusts are 2 slugs each, so our total volume is 20 slugs. 80 stones divided by 20 slugs is 4 so our Average Weight per Unit of Volume is 4. If we were to make that mix into some gauntlets, our gauntlets would weigh 410 since gauntlets have a volume of 10, if we were to make that mix into a scimitar the scimitar, which has a volume of 6, our scimitar would weigh 4 stones * 6. The excess material which we do not use is thrown away, hence this is not really compression at all, it is simply using what you need from the ingot, plate, or wire and throwing the rest away. To further explain, if we take an iron bar, which has a weight of 51 and a volume of 10, and make it into a broadsword which requires a volume of 7, our broadsword would weigh (51/10)*7 stones because we would only use 7 out of 10 of the volume, the other 3 is thrown away. At this point I would like to note that Dragon Realms always rounds DOWN, so if your item is 34.9999999 stones, upon completion it will be 34 stones, just like if your item would be 58.12345 stones, upon completion it will weigh 58 stones.

	Another form of compression is an unintended but useful error in the mechanics of mixing in which the weight of something is added but not the volume. This has never been fixed, and will not be fixed until forging 2.0 is out due to the fact that without it we would have no way of making items heavier. To explain, compression of this type is based on even and odd numbers of volume. If you mix two different types of metal together, and one has an odd volume number while the other has an even volume number, 1 unit of volume will compress and its weight will be added but not its volume. This is a bit confusing so please bear with me as I attempt to explain. If you have 1 iron bar which has a volume of 10 and it with 1 zinc slug which has a volume of 1, the zinc slugs weight will be added but not its volume, thus 1 iron bar (volume 10, weight 51) plus 1 zinc slug (volume 1, weight 5) makes a mass with a volume of 10 and a weight of 56. By further example, if you mix two zinc slugs together, again each having a weight of 5 and a volume of 1, this will give us 10 stones total at 2 slugs volume. If then we add 3 lead slugs (each having volume of 1 and weight of 8) then by normal thinking it SHOULD give us 5+5+8+8+8=34 weight at 1+1+1+1+1=5 volume, but it does not due to compression. 2 (even) zinc slugs plus 3 (odd) lead slugs will only give us a volume of 4 because 1 unit of volume will compress, the weight will still be added so you will still have 34 stones of material, but due to compression (even+odd, or odd+even) 1 unit of volume will compress so we will only have a volume of 4. Again, to explain, 2+1=2, 3+2=4, 5+4=8, and so fourth due to compression. Theoretically you can make items infinitely heavier this way, since 2+1=2, you can continually add another single unit of volume to it and the weight will be added but, once again, not the volume, so 2+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1=2. A common example of this is 23 stone short swords and 39 stone katars. To make a 23 stone short sword or 39 stone katar, you start with an iron bar, which is 51 stones at 10 slugs of volume, and compress single slugs into it one at a time until you reach 78 stones, you can use any non-iron slug metal slug you want for this such a 2 nickel slugs and 3 zinc slugs, or 2 copper slug and 3 zinc slugs, or 2 lead slugs 1 zinc slug and 1 copper slug, or any other combonation as long as they are a metal other than iron they will compress when mixed one at a time because 10+1+1+1+1+1+1+1+1+1+1+1+1+1+1=10. each time you mix a single slug into the iron bar its weight will be added but NOT its volume.		Another form of compression is an unintended but useful error in the mechanics of mixing in which the weight of something is added but not the volume. This has never been fixed, and will not be fixed until forging 2.0 is out due to the fact that without it we would have no way of making items heavier. To explain, compression of this type is based on even and odd numbers of volume. If you mix two different types of metal together, and one has an odd volume number while the other has an even volume number, 1 unit of volume will compress and its weight will be added but not its volume. This is a bit confusing so please bear with me as I attempt to explain. If you have 1 iron bar which has a volume of 10 and it with 1 zinc slug which has a volume of 1, the zinc slugs weight will be added but not its volume, thus 1 iron bar (volume 10, weight 51) plus 1 zinc slug (volume 1, weight 5) makes a mass with a volume of 10 and a weight of 56. By further example, if you mix two zinc slugs together, again each having a weight of 5 and a volume of 1, this will give us 10 stones total at 2 slugs volume. If then we add 3 lead slugs (each having volume of 1 and weight of 8) then by normal thinking it SHOULD give us 5+5+8+8+8=34 weight at 1+1+1+1+1=5 volume, but it does not due to compression. 2 (even) zinc slugs plus 3 (odd) lead slugs will only give us a volume of 4 because 1 unit of volume will compress, the weight will still be added so you will still have 34 stones of material, but due to compression (even+odd, or odd+even) 1 unit of volume will compress so we will only have a volume of 4. Again, to explain, 2+1=2, 3+2=4, 5+4=8, and so fourth due to compression. Theoretically you can make items infinitely heavier this way, since 2+1=2, you can continually add another single unit of volume to it and the weight will be added but, once again, not the volume, so 2+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1=2. A common example of this is 23 stone short swords and 39 stone katars. To make a 23 stone short sword or 39 stone katar, you start with an iron bar, which is 51 stones at 10 slugs of volume, and compress single slugs into it one at a time until you reach 78 stones, you can use any non-iron slug metal slug you want for this such a 2 nickel slugs and 3 zinc slugs, or 2 copper slug and 3 zinc slugs, or 2 lead slugs 1 zinc slug and 1 copper slug, or any other combonation as long as they are a metal other than iron they will compress when mixed one at a time because 10+1+1+1+1+1+1+1+1+1+1+1+1+1+1=10. each time you mix a single slug into the iron bar its weight will be added but NOT its volume.

Maintenance script: /* Compression */

2010-05-09T01:23:30Z

Compression

← Older revision		Revision as of 20:23, 8 May 2010
Line 155:		Line 155:
	Anyone who wants to know, can know, I just don't want or need to know everything, its just what I need to know that matters,		Anyone who wants to know, can know, I just don't want or need to know everything, its just what I need to know that matters,

	Veldehar		Veldehar




			As an additional note from Gavinne, there are two forms of 'compression' so the term can be misleading if you do not know which form is being spoken of.

			One form of compression, which really isn't compression at all, is when you have a 200 stone ingot and pound it into a scimitar, yet the scimitar only weighs 22 stones. Folks began calling this 'compression' due to a lack of understanding and hopefully this will help clear some things up. The general formula for determining an items weight is (Total Mix Weight/Total Mix Volume)Volume Required For Item, or (W/V)R. Basically, if you have a 5 pound block of steel which has a volume of 3 cubic feet and make something out of it that only needs to use 1 cubic feet, your item will weigh (5/3)1 pounds, the excess metal is thrown away since it is not used. To further this example, lets say we have a mix like '3 tin slugs, melt and mix them together, add 2 dusts, melt and mix, add 2 more dusts, melt and mix, add an iron bar, melt and mix, then add a final dust, melt and stir.' or, in short, 3 tin slugs MIX 2 dusts MIX 2 dusts MIX 1 iron bar MIX 1 dust MIX. The final dust is to make it steel so that will not be counted as it does not add weight or volume (when carbonizing steel the volume and weight of the dust used to carbonize is not added) so we will not include that, this leaves us with 4 dusts, 3 tin slugs, and an iron bar. iron bar is 51 stones, tin slugs are 7 stones each, dusts are 2 stones each, thus our total weight is 80 stones. For volume, iron bar is 10 slugs, tin slugs are 1 slug each, dusts are 2 slugs each, so our total volume is 20 slugs. 80 stones divided by 20 slugs is 4 so our Average Weight per Unit of Volume is 4. If we were to make that mix into some gauntlets, our gauntlets would weigh 410 since gauntlets have a volume of 10, if we were to make that mix into a scimitar the scimitar, which has a volume of 6, our scimitar would weigh 4 stones * 6. The excess material which we do not use is thrown away, hence this is not really compression at all, it is simply using what you need from the ingot, plate, or wire and throwing the rest away. To further explain, if we take an iron bar, which has a weight of 51 and a volume of 10, and make it into a broadsword which requires a volume of 7, our broadsword would weigh (51/10)*7 stones. At this point I would like to note that Dragon Realms always rounds DOWN, so if your item is 34.9999999 stones, upon completion it will be 34 stones, just like if your item would be 58.12345 stones, upon completion it will weigh 58 stones.

			Another form of compression is an unintended but useful error in the mechanics of mixing in which the weight of something is added but not the volume. This has never been fixed, and will not be fixed until forging 2.0 is out due to the fact that without it we would have no way of making items heavier. To explain, compression of this type is based on even and odd numbers of volume. If you mix two different types of metal together, and one has an odd volume number while the other has an even volume number, 1 unit of volume will compress and its weight will be added but not its volume. This is a bit confusing so please bear with me as I attempt to explain. If you have 1 iron bar which has a volume of 10 and it with 1 zinc slug which has a volume of 1, the zinc slugs weight will be added but not its volume, thus 1 iron bar (volume 10, weight 51) plus 1 zinc slug (volume 1, weight 5) makes a mass with a volume of 10 and a weight of 56. By further example, if you mix two zinc slugs together, again each having a weight of 5 and a volume of 1, this will give us 10 stones total at 2 slugs volume. If then we add 3 lead slugs (each having volume of 1 and weight of 8) then by normal thinking it SHOULD give us 5+5+8+8+8=34 weight at 1+1+1+1+1=5 volume, but it does not due to compression. 2 (even) zinc slugs plus 3 (odd) lead slugs will only give us a volume of 4 because 1 unit of volume will compress, the weight will still be added so you will still have 34 stones of material, but due to compression (even+odd, or odd+even) 1 unit of volume will compress so we will only have a volume of 4. Again, to explain, 2+1=2, 3+2=4, 5+4=8, and so fourth due to compression. Theoretically you can make items infinitely heavier this way, since 2+1=2, you can continually add another single unit of volume to it and the weight will be added but, once again, not the volume, so 2+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1=2. A common example of this is 23 stone short swords and 39 stone katars. To make a 23 stone short sword or 39 stone katar, you start with an iron bar, which is 51 stones at 10 slugs of volume, and compress single slugs into it one at a time until you reach 78 stones, you can use any non-iron slug metal slug you want for this such a 2 nickel slugs and 3 zinc slugs, or 2 copper slug and 3 zinc slugs, or 2 lead slugs 1 zinc slug and 1 copper slug, or any other combonation as long as they are a metal other than iron they will compress when mixed one at a time because 10+1+1+1+1+1+1+1+1+1+1+1+1+1+1=10. each time you mix a single slug into the iron bar its weight will be added but NOT its volume.

			~Gavinne

	==See also==		==See also==